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Question

The coefficient of x5 in the expansion of (1+x)21+(1+x)22+...+(1+x)30 is

A
51C5
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B
9C5
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C
31C621C6
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D
30C520C5
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Solution

The correct option is C 31C621C6
(1+x)21+(1+x)22+...+(1+x)30
=(1+x)21[(1+x)101(1+x)1]=1x[(1+x)31(1+x)21]
Coefficient of x5 in the given expression is equal to coefficient of x6 in [(1+x)31(1+x)21], which is given by 31C621C6

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