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Question

The coefficient of x5 in the expansion of (x2x2)5 is:

A
83
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B
82
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C
81
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D
0
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Solution

The correct option is B 81
(x2x2)5=(x+1)5.(x2)5

Coefficient of x5 is =(0,5)+(5,0)+(2,3)+(3,2)+(4,1)+(1,4)

=25+1+5C2.5C3(2)3+5C3.5C2(2)2+5C4.5C1(2)+5C1.5C4(2)4

=32+1800+40050+400=81

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