The coefficient of x53 in the expansion of ∑100m=0100Cm(x−3)100−m.2m is
A
100C47
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B
100C53
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C
−100C53
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D
−100C100
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Solution
The correct option is C−100C53 The above is the general term of ((x−3)+2)100 =(x−1)100 =(1−x)100 Hence re-writing the general term we get Tr+1=(−1)r100Crxr Now the term consisting of x53 is T54=(−1)53100C53 =−100C53