The coefficient of x6 in (1+x)6+(1+x)7......+(1+x)15 is
A
16C9
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B
16C5−6C5
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C
16C6−1
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D
none of these
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Solution
The correct option is A16C9 Coefficient of x6 is 6C6+7C6+8C6+....15C6 Now nCr+n+1Cr=n+1Cr+1 ...(i) [6C6−7C7]+7C7+7C6+8C6+....15C6 =0+7C7+7C6+8C6+....15C6 =8C7+8C6+9C6+....15C6 using i =9C7+9C6+10C6+....15C6 : : =15C7+15C6 =16C7 =16C9