wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient ofx7 in (1xx2+x3)6 is


A

-144

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

132

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

144

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

-132

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

-144


(1xx2+x3)6=(1x)6(1x2)6=(16C1x+6C2x26C3x3+6C4x46C5x5+6C6x6)×(16C1x2+6C2x46C3x6+6C4x86C5x10+6C6x12)
Coefficient of x7=(16C1x6C3)+(16C3x6C2)+(16C5x6C1)
=120-300+36=-144


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What is Binomial Expansion?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon