The correct option is D 0
Consider the following
Tr+1=nCran−rbr
Applying to the above question we get
Tr+1=(−1)r9Cr(x22)9−r(2x−1)r
Tr+1=(−1)r9Crx18−3r22r−9
Therefore 18−3r=7 for the coefficient of x7
18−3r=7
11=3r
r=113 but r has to be a whole number.
Hence the coefficient of x7 is zero that is there is no x7 term in the expansion