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Question

The coefficient of x7 in (x22−2x)9 is

A
56
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B
14
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C
14
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D
0
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Solution

The correct option is D 0
Consider the following
Tr+1=nCranrbr
Applying to the above question we get
Tr+1=(1)r9Cr(x22)9r(2x1)r
Tr+1=(1)r9Crx183r22r9
Therefore 183r=7 for the coefficient of x7
183r=7
11=3r
r=113 but r has to be a whole number.
Hence the coefficient of x7 is zero that is there is no x7 term in the expansion

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