wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of x7 in the expansion of (1−x−x2+x3)6. is?

A
132
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
144
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
-132
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
-144
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D -144
(1xx2+x3)6=(1x)6(1x2)6=(16C1x+6C2x26C3x3+6C4x46C5x5+6C6x6)(16C1x2+6C2x46C3x6+)
coefficient of x7 is
6C1.6C36C3.6C2+6C5.6C1=6×2020×15+6×6=144

flag
Suggest Corrections
thumbs-up
58
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
How to Expand?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon