The coefficient of x7in the expansion of (1−x−x2+x3)6 is
A
-132
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B
-144
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C
132
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D
144
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Solution
The correct option is B -144 (1−x−x2+x3)6=[(1−x)−x2(1−x)]6=(1−x)6(1−x2)6=(1−6x+15x2−20x3+15x4−6x5+x6)×(1−6x2+15x4−20x6+15x8−6x10+x12)Coefficient of x7=(−6)(−20)+(−20)(15)+(−6)(−6)=−144