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Byju's Answer
Standard XII
Mathematics
Binomial Expression
The coefficie...
Question
The coefficient of
x
7
in the expansion of
(
1
−
x
−
x
2
+
x
3
)
6
is
A
−
132
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B
−
144
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C
132
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D
144
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Solution
The correct option is
C
−
144
Coff. of
x
7
in exp. of
(
1
−
x
−
x
2
+
x
3
)
6
is
(
1
−
x
−
x
2
+
x
3
)
6
=
[
(
1
−
x
)
−
x
2
(
1
−
x
)
]
6
⇒
(
1
−
x
−
x
2
+
x
3
)
6
=
(
1
−
x
2
)
6
(
1
−
x
)
6
⇒
(
1
−
6
x
2
+
6
C
2
x
4
−
6
6
C
3
x
6
+
6
C
4
x
8
−
6
C
5
x
10
+
x
12
)
(
1
−
6
x
+
6
C
2
x
2
−
6
C
3
x
3
+
6
C
4
x
4
−
6
x
5
+
x
6
)
∴
Coff. of
x
7
is
(
−
6
)
(
−
6
C
3
)
+
6
C
2
(
−
6
C
3
)
+
(
−
6
)
(
−
6
)
⇒
6
×
20
−
15
×
20
+
36
Coff.
(
x
2
)
=
−
144
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