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Question

The coefficient of x7 in the expansion of (1xx2+x3)6 is

A
132
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B
144
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C
132
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D
144
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Solution

The correct option is C 144
Coff. of x7 in exp. of (1xx2+x3)6 is

(1xx2+x3)6=[(1x)x2(1x)]6

(1xx2+x3)6=(1x2)6(1x)6

(16x2+6C2x466C3x6+6C4x86C5x10+x12)(16x+6C2x26C3x3+6C4x46x5+x6)

Coff. of x7 is (6)(6C3)+6C2(6C3)+(6)(6)

6×2015×20+36

Coff. (x2)=144

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