wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of x8 in the polynomial (x1)(x2)(x3)...(x10) is

A
1025
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1240
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1320
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1440
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 1320
(x1)(x2)x23x+2x2(2+1)x+(2+1)
(x1)(x2)(x3)x3(1+2+3)x2+(1×2+1×3+2×3)x+(1×2×3)
(xa1)(xa2)....(xan)=xn(a1+a2+...an)xn1+(a1a2....an)
(x1)(x2)(x3)....(x10)
x8[2+3+4+...+10]+2[3+4+....+10]+...9×10
=1×54+2×52+3×49+....9×10
=1320 Required coefficient of x8

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon