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Question

The coefficient of x9 in the expansion of (1+x)(1+x2)(1+x3).(1+x100) is .

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Solution

The number of possible combination for x9 will be
x0x9x1x8x2x7x3x6x4x5x1x2x6x1x3x5x2x3x4
Coefficient of all the terms will be =1
Total cofficient =8

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