You visited us 1 times! Enjoying our articles? Unlock Full Access!

Quadratic Equation

The coefficie...

Question

The coefficient of $x$ in the equation $a x^{2} + b x + c = 0$ was wrongly taken as $17$ instead of $13$ & its roots were $- 2, - 15.$ Actual roots are

-2, 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-3, -10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-4, -9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-5, -6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
-3, -10

Product of the roots $= - 2 \times - 15 = 30$

Therefore, equation becomes $x^{2} + 13 x + 30$

$= (x + 10) (x + 3)$

$\Rightarrow x = - 10, - 3$
Watch next video for more explanations

Suggest Corrections

Similar questions

The coefficient of $x$ in the equation $a x^{2} + b x + c = 0$ was wrongly taken as $17$ instead of $13$ & its roots were $- 2, - 15$ . Actual roots are _____.

Q. The coefficient of x in the equation

a x^{2} + b x + c = 0

was wrongly taken as 17 instead of 30 and its roots came out to be -2, -15. The actual roots were:

Q. The coefficient of

x

in the quadratic equation

a x^{2} + b x + c = 0

was wrongly taken as

17

in place of

13

and its roots were found to be

- 2

and

- 15

, the actual roots of the equation are

Q. The coefficient of

x

in the equation

x^{2} + p x + q = 0

, was wrongly written as

17

in place of

13

and the roots thus found to be

- 2

and

- 15

. The roots of the correct equation is/are

The coefficient of x in the equation $x^{2}$ + p $x$ + q = 0 was taken as 17 in place of 13, its roots were found to be -2 and -15, the roots of the original equation are

Join BYJU'S Learning Program

The coefficient of x in the equation ax2+bx+c=0 was wrongly taken as 17 instead of 13 & its roots were −2, −15. Actual roots are

The correct option is B -3, -10 Product of the roots =−2×−15=30 Therefore, equation becomes x2+13x+30 =(x+10)(x+3) ⇒x=−10, −3 Watch next video for more explanations

The coefficient of $x$ in the equation $a x^{2} + b x + c = 0$ was wrongly taken as $17$ instead of $13$ & its roots were $- 2, - 15.$ Actual roots are

The correct option is B
-3, -10

Product of the roots $= - 2 \times - 15 = 30$

Therefore, equation becomes $x^{2} + 13 x + 30$

$= (x + 10) (x + 3)$

$\Rightarrow x = - 10, - 3$
Watch next video for more explanations