The coefficient of x in the equation $x^{2}$ + px +q =0 was taken as 17 in place of 13, its roots were found to be -2 and -15, the roots of the original equation are

Q. If the coefficient of

x

in the quadratic equation

x^{2} + p x + q = 0

was taken as

17

in place of

13

, then its roots were found to be

- 2

and

- 15

.
The roots of the original equation are

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The coefficient of x in the equation x2+px+q=0 was wrongly written as 17 in place of 13 and the roots thus found was −2 and −15. Then the roots of the correct equation are

The correct option is C −3,−10Correct equation isx2+13x+q=0 (1)Incorrect equation isx2+17x+q=0 (2)Given that roots of Eq. (2) are −2 and −15. Therefore, product of the roots of incorrect equation is q=(−2)(−15)=30. From (1), the correct equation isx2+13x+30=0∴x=−3,−10

The coefficient of $x$ in the equation $x^{2} + p x + q = 0$ was wrongly written as $17$ in place of $13$ and the roots thus found was $- 2$ and $- 15 .$ Then the roots of the correct equation are