The coefficient of $x$ in the expansion of $(x + 4)^{2}$ is

16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $8$
$(x + 4)^{2} = x^{2} + 16 + 8 x$
The numerical values of the terms in a polynomial are called coefficients of the polynomial.
So, $8$ is the coefficient of $x$ .

Suggest Corrections

Similar questions

(2 x^{2} - 8) (x - 4)^{2}

x^{2}

x^{4}

\frac{3 x - 8}{4 - 4 x + x^{2}}

(2 x^{2} - 8) (x - 4)^{2}

x^{3}

x^{16}

(2 - x)^{20}

x^{4}

{(4 x^{2} + \frac{3}{x})}^{8}

Join BYJU'S Learning Program