The coefficient of x in the quadratic equation $x^{2} + p x + q = 0$ was taken as 17 in place of 13 , its roots were found to be -2 and -15 . Find the roots of the original equation.

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Solution

Here q = -2 $\times$ -15 = 30, correct value of p = 13
$∴ x^{2}$ + 13x + 30 + 30 = 0 or (x + 10)(x + 3) = 0
$∴$ Roots are -10, -3.

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Q. If the coefficient of

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The coefficient of x in the quadratic equation x2+px+q=0 was taken as 17 in place of 13 , its roots were found to be -2 and -15 . Find the roots of the original equation.

Here q = -2 × -15 = 30, correct value of p = 13∴x2 + 13x + 30 + 30 = 0 or (x + 10)(x + 3) = 0∴ Roots are -10, -3.

The coefficient of x in the quadratic equation $x^{2} + p x + q = 0$ was taken as 17 in place of 13 , its roots were found to be -2 and -15 . Find the roots of the original equation.

Here q = -2 $\times$ -15 = 30, correct value of p = 13
$∴ x^{2}$ + 13x + 30 + 30 = 0 or (x + 10)(x + 3) = 0
$∴$ Roots are -10, -3.