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Question

The coefficient of xn in expansion of (1+x)(1−x)n, is

A
(n1)
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B
(1)n(1n)
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C
(1)n1(n1)2
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D
(1)n1n
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Solution

The correct option is C (1)n(1n)
The coefficient of xn in expansion of (1+x)(1x)n
= Coefficient of xn+ Coefficient of xn1
=(1)nn!n!0!+(1)n1n!1!(n1)!
=(1)n[n!n!0!n!1!(n1)!]
=(1)n[n!n!0!n!1!(n1)!]
=(1)n(1n)

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