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Question

The coefficient of xn in (1+x)2(1āˆ’x)3 is :


A

3n2+2n+1

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B

2n2+2n+1

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C

n2+n+1

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D

2n2+2n+1

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Solution

The correct option is B

2n2+2n+1


(1+x)2(1x)3=(1+2x+x2)(1x)3

Coeff.ofxn=(Coeff.ofxn+2.coeff.xn1+

coeff.ofxn2)in(1x)3 .

=n+2C3+2.n+1C2+nC2

=[(n+2) (n+1)+2(n+1)n+n(n-1)]/2

=2n2+2n+1

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