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Question

The coefficient of xn in the expansion of (1x)(1x)n is :

A
n1
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B
(1)n(1+n)
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C
(1)n1(n1)2
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D
(1)n1 n
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Solution

The correct option is B (1)n(1+n)
(1x)(1x)n
=(1x)[(1+n(x)++nCn1(x)n1+nCn(x)n]

the coefficient of xn is
nCn(1)n nCn1(1)n1
=(1)n+(1)n n
=(1)n(1+n)

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