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Question

The coefficient of xn in the expansion of (1+x)(1−x)n is

A
(1)n1n
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B
(1)n(1n)
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C
(1)n1(n2)2
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D
(n1)
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Solution

The correct option is C (1)n(1n)
We have
Coefficient of xn in (1+x)(1x)n
= Coefficient of xn in (1x)n + Coefficient of xn1 in (1x)n
=(1)nnCn+(1)n1nCn1=(1)n(1n)

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