The coefficient of xn in the polynomial (x+2n+1C0)(x+2n+1C1)(x+2n+1C2)+....(x+2n+1Cn)
A
2n+1
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B
22n+1−1
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C
22n
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D
22n+1+1
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Solution
The correct option is C22n The required coefficient will be 2n+1C0+2n+1C1+2n+1C2+2n+1C3...2n+1Cn Now 2n+1Cr=2n+1C2n+1−r Now (1+x)2n+1|x=1=2n+1C0+2n+1C1+2n+1C2+2n+1C3...2n+1C2n The middle terms will 2n+1Cn and 2n+1Cn+1 Hence 22n+1=2n+1C0+2n+1C1+2n+1C2+2n+1C3...2n+1C2n =2[2n+1C0+2n+1C1+2n+1C2+2n+1C3...2n+1Cn−1]+2n+1Cn+2n+1Cn+1 =2[2n+1C0+2n+1C1+2n+1C2+2n+1C3...2n+1Cn] Hence 22n+1=2[2n+1C0+2n+1C1+2n+1C2+2n+1C3...2n+1Cn] 2n+1C0+2n+1C1+2n+1C2+2n+1C3...2n+1Cn=22n Thus the coefficient is 2n.