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Question

The coefficient of xr[0rn1] in the expression of (x+2)n1+(x+2)n2.(x+1)+(x+2)n3.(x+1)2+...+(x+1)n1 is

A
nCr(2r1)
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B
nCr(2nr1)
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C
nCr(2r+1)
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D
nCr(2nr+1)
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Solution

The correct option is A nCr(2nr1)
Given expression is equal to np=1(x+3)(np)×(x+2)(p1)
Which is equal to (x+3)(n1)×(np=1((x+2)(x+3))(p1))=(x+3)n(x+2)n
So,coefficient of xr is nCr×(3(nr)2(nr))

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