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Question

The coefficient w,x,y,z in the reaction wCr2O27+xFe2+yCr3++zFe3++H2O is:

A
1,2,6,6
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B
6,1,2,4
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C
1,6,2,6
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D
1,2,4,6
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Solution

The correct option is B 1,6,2,6
Cr2O27+Fe+2Cr+3+Fe+3+H2O
Oxidation 6 2 3 3
state
Step 1
Ox. half reaction Fe+2Fe+3
Reduction half reaction Cr2O27Cr+3
Step 2
Balancing all atoms except O & H
Ox. half reaction Fe+2Fe+3
Reduction half reaction Cr2O272Cr+3
Step 3
Balancing O by adding H2O
Ox. half reaction Fe+2Fe+3
Reduction half reaction Cr2O272Cr+3+7H2O
Step 5
Balancing H by adding H+1 ions
Ox. half reaction Fe+2Fe+3
Reduction half reaction Cr2O27+14H+12Cr+3+7H2O
Step 6
Balancing the chrages
Ox. half reaction Fe+2Fe+3+e1
Reduction half reaction Cr2O27+14H+1+6e12Cr+3+7H2O
Step 7
Make number of electrons electrons
multiply oxidation reaction by 6
Ox. half reaction 6Fe+26Fe+3+6e1
Reduction half reaction Cr2O27+14H+1+6e12Cr+3+7H2O
Step 8
Adding both the half reactions
6Fe+2+Cr2O27+14H+6Fe+3+2Cr+3+7H2O
SO w=1
x=6
y=2
z=6

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