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Question

The coefficients of xn in the polynomial (x+nC0)(x+3nC1)(x+5nC2)...(x+(2n+1)nCn) is

A
n2n
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B
n.2n+1
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C
(n+1).2n
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D
n.2n1
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Solution

The correct option is C (n+1).2n
Given polynomial is
(x+nC0).(x+3nC1).(x+5nC2)...(x+(2n+1)nCn)=xn+1+xn{nC0+3nC1+5.nC2+...(2n+1)nCn}+xn1(...)+...
Coefficients of xn in the expansion is
nr=0(2r+1)nCr=nr=02rnCr+nr=0nCr=2nr=0r.nr.n1Cr1+2n
=2nnr=0n1Cr1+2n=2n.2n1+2n=(n+1)2n

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