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Byju's Answer
Standard XII
Mathematics
Local Maxima
The coefficie...
Question
The coefficients of
x
n
in the polynomial
(
x
+
n
C
0
)
(
x
+
3
n
C
1
)
(
x
+
5
n
C
2
)
.
.
.
(
x
+
(
2
n
+
1
)
n
C
n
)
is
A
n
.2
n
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B
n
.2
n
+
1
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C
(
n
+
1
)
.2
n
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D
n
.2
n
−
1
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Solution
The correct option is
A
(
n
+
1
)
.2
n
Given,
(
x
+
n
C
0
)
(
x
+
3
n
C
1
)
(
x
+
5
n
C
2
)
.
.
.
(
x
+
(
2
n
+
1
)
n
C
n
)
=
x
n
+
1
+
x
n
[
n
C
0
+
3
n
C
1
+
5
n
C
2
+
.
.
.
.
.
(
2
n
+
1
)
n
C
n
]
+
x
n
−
1
(
.
.
.
)
.
.
Thus the coefficient of
x
n
in the expression is
n
∑
r
=
0
(
2
r
+
1
)
n
C
r
=
n
∑
r
=
0
(
2
r
)
n
C
r
+
n
∑
r
=
0
(
1
)
n
C
r
=
2
∑
n
r
=
0
(
n
)
n
−
1
C
r
−
1
+
2
n
=
2
n
∑
n
r
=
0
n
−
1
C
r
−
1
+
2
n
=
2
n
.
2
n
−
1
+
2
n
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0
Similar questions
Q.
The coefficient of
x
n
in the polynomial
(
x
+
2
n
+
1
C
0
)
(
x
+
2
n
+
1
C
1
)
(
x
+
2
n
+
1
C
2
)
+
.
.
.
.
(
x
+
2
n
+
1
C
n
)
Q.
If
(
1
+
x
)
n
=
n
∑
r
=
0
n
C
r
x
n
,
then
C
0
1
⋅
2
2
2
+
C
1
2
⋅
3
2
3
+
C
2
3
⋅
4
2
4
+
⋯
+
C
n
(
n
+
1
)
(
n
+
2
)
2
n
+
2
is equal to
Q.
The coefficient of
x
n
in the polynomial
(
x
+
n
C
0
)
(
x
+
3
⋅
n
C
1
)
⋯
(
x
+
(
2
n
+
1
)
⋅
n
C
n
)
is
Q.
I
f
(
1
+
x
)
n
=
C
0
+
c
1
x
+
.
.
.
+
C
n
x
n
+
,
t
h
e
n
C
1
C
0
+
2
C
2
C
1
+
3
C
3
C
2
+
.
.
.
.
.
+
n
C
n
C
n
−
1
i
s
Q.
If
n
C
0
2
n
+
2.
n
C
1
2
n
+
3.
n
C
2
2
n
+
…
.
(
n
+
1
)
n
C
n
2
n
=
16
, then the value of '
n
' is:
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