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Question

The coefficients of xn in the polynomial (x+nC0)(x+3nC1)(x+5nC2)...(x+(2n+1)nCn) is

A
n.2n
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B
n.2n+1
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C
(n+1).2n
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D
n.2n1
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Solution

The correct option is A (n+1).2n
Given,
(x+nC0)(x+3nC1)(x+5nC2)...(x+(2n+1)nCn)
=xn+1+xn[nC0+3nC1+5nC2+.....(2n+1)nCn]+xn1(...)..
Thus the coefficient of xn in the expression is
nr=0(2r+1)nCr=nr=0(2r)nCr+nr=0(1)nCr
=2nr=0(n)n1Cr1+2n=2nnr=0n1Cr1+2n=2n.2n1+2n

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