The coil of area 0-1 m2 has 500 turns- After placing the coil in a magnetic field of strength 4- 10-4Wb-m2- if rotated through 90- in 0-1 s- the average emf induced in the coil is

E= NBA(cosθ_2 cosθ_1)/ t = 500× 4× 10^ 4× 0.1(cos90 cos0)/0.1=0.2V ...

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Byju's Answer

Standard XI

Physics

Dependence on Area and Orientation

The coil of a...

Question

The coil of area 0.1 $m^{2}$ has 500 turns. After placing the coil in a magnetic field of strength $4 \times 10^{- 4} W b / m^{2}$ , if rotated through $90^{\circ}$ in 0.1 s, the average emf induced in the coil is

0.012 V

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0.05 V

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0.1 V

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0.2 V

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Solution

The correct option is D 0.2 V
$e = \frac{- N B A (c o s θ_{2} - c o s θ_{1})}{△ t}$
$= - \frac{500 \times 4 \times 10^{- 4} \times 0.1 (c o s 90 - c o s 0)}{0.1} = 0.2 V$

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The coil of area 0.1 m2 has 500 turns. After placing the coil in a magnetic field of strength 4× 10−4Wb/m2, if rotated through 90∘ in 0.1 s, the average emf induced in the coil is

The correct option is D 0.2 Ve=−NBA(cosθ2−cosθ1)△ t =−500× 4× 10−4× 0.1(cos90−cos0)0.1=0.2V

The coil of area 0.1 $m^{2}$ has 500 turns. After placing the coil in a magnetic field of strength $4 \times 10^{- 4} W b / m^{2}$ , if rotated through $90^{\circ}$ in 0.1 s, the average emf induced in the coil is

The correct option is D 0.2 V
$e = \frac{- N B A (c o s θ_{2} - c o s θ_{1})}{△ t}$
$= - \frac{500 \times 4 \times 10^{- 4} \times 0.1 (c o s 90 - c o s 0)}{0.1} = 0.2 V$