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Inductors in Circuits

The cold junc...

Question

The cold junction of a thermocouple is at $0^{0} C$ and the thermo emf (in volts ) as a function of the temperature 't' of the hot junction is given by $E = [10 \times 10^{- 6} t - \frac{1}{40} \times 10^{- 6} t^{2}]$
The neutral temperature and the maximum emf produced are respectively

200^{0} C, 1 m V

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400^{0} C, 2 m V

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100^{0} C, 1 m V

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200^{0} C, 2 m V

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Solution

The correct option is A $200^{0} C, 1 m V$
We know that neutral temperature is given by: $\frac{d E}{d T} = 0$
So, on differentiating the above equation we get: $T_{n} = 200 C$
Now put the value of $T_{n}$ in the above equation we find the value of maximum emf which as follow:
( $200 \times 10^{- 5} - 10^{- 3}) = 10^{- 3} = 1 m V$

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