The color of $K M n O_{4}$ is due to

d - d

transition

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Ligand to metal charge transfer

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Metal to ligand charge transfer

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None of the above

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Solution

The correct option is B Ligand to metal charge transfer
In $K M n O_{4}$ $M n$ is in $+ 7$ oxidation state. So $M n$ has no d-electrons and thus possesses the tendency to accept electrons form the ligands. Due to this ligand to metal charge transfer, $K M n O_{4}$ has a intense pink colour

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