Question

The color of $KMn{O}_4$ is due to

• A. $d-d$ transition
• B. Ligand to metal charge transfer
• C. Metal to ligand charge transfer
• D. None of the above

Answer 1

The correct option is B Ligand to metal charge transfer

In $KMn{O}_4$ $Mn$ is in $+7$ oxidation state. So $Mn$ has no d-electrons and thus possesses the tendency to accept electrons form the ligands. Due to this ligand to metal charge transfer, $KMn{O}_4$ has a intense pink colour