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Question

The color of KMnO4 is due to:


A

M → L charge transfer transition

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B

d - d transition

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C

L → M charge transfer transition

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D

σ – σ* transition

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Solution

The correct option is C

L → M charge transfer transition


L→M charge transfer transition

In [MnO4]¯, the electronic configuration of Mn is [Ar]3d0. As there are no d electrons, the colour is not due to a d-d transition of electrons. In this case, the electron transition takes place from the orbital of the ligand to the empty d orbital of Mn.


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