The colorless species is:

V {C l}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

V O {S O}_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{N a}_{3} {V O}_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[V {(H_{2} O)}_{6} {S O}_{4}] . H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${N a}_{3} {V O}_{4}$
$V C l_{3}$ is green.
$V O S O_{4}$ is blue.

$N a_{3} V O_{4}$ is colorless vanadium is present in +5 oxidation state .it does not have any unpaired electron.
$[V {(H_{2} O)}_{6} {S O}_{4}]$ . $H_{2} O$ is purple.

Suggest Corrections

Similar questions

V C l_{3}

V O S O_{4}

N a_{3} V O_{4}

$[V {(H_{2} O)}_{6}] S O_{4} . H_{2} O$

(I) V C l_{3} (I I) V O S O_{4} (I I I) N a_{3} V O_{4} (I V) [V (H_{2} O)_{6}] S O_{4} . H_{2} O

H_{2} {S O}_{4}

Join BYJU'S Learning Program