The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes? [Co(NH3)6]+3, [Co(CN)6]3−, [Co(H2O)6]+3
A
[Co(CN)6]3−>[Co(NH3)6]+3,[Co(H2O)6]+3
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B
[Co(NH3)6]+3>[Co(H2O)6]+3,[Co(CN)6]3−,
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C
[Co(H2O)6]+3> [Co(NH3)6]+3, [Co(CN)6]3−
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D
[Co(CN)6]3−> [Co(H2O)6]+3, [Co(NH3)6]+3
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Solution
The correct option is A[Co(CN)6]3−>[Co(NH3)6]+3,[Co(H2O)6]+3 CFSE increases when strong field ligand is attached as a result wavelength decreases in case of very strong field ligands like CN− than NH3 than H2O