Question

The colourless and odourless gas (B) is:

• A. $CO$
• B. $C{O}_2$
• C. $H_2$
• D. $H_{2}O$

Answer 1

The correct option is C $H_2$

DU in $A=\frac{(2n_C+2)-H}{2}=\frac{(2\times 9+2)-12}{2}=4^{\circ }$

(It shows benzene ring which is also confirmed by the oxidation of (A) to benzoic acid (PhCOOH).)

i. Reaction of Na with (A) shows that it contains (-OH) group.

(A) is chiral, so the possible structures of (A) can be
(II) will give iodoform test.

But compound (A) does not give iodoform test. So the structure of (A) is (I).