The colourless species is (are) :

VCl

_{3}

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VOSO

_{4}

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_{3}

_{4}

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[V(H

_{2}

)

_{6}

] SO

_{4}

_{2}

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Solution

The correct option is B Na $_{3}$ VO $_{4}$
Compound with zero unpair electron will be colourless.
$V C l_{3};_{23} V^{3 +}; [A r]^{18} 3 d^{2} = 2$ unpaired electrons
$V O^{+ 2}; V^{4 +}; [A r]^{18} 3 d^{2} = 1$ unpaired electron.
$[V O_{4}]^{3 -}; V^{5 +}; [A r]^{18} 3 d^{0} =$ no unpaired electron so colourless.
$[V (H_{2} O)_{6}]^{2 +}; V^{2 +} : [A r]^{18} 3 d^{3} = 3$ unpaired electrons.

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Similar questions

Q. Amongst

T i C l_{6}^{2 -}, C o F_{6}^{3 -}, {C u}_{2} {C l}_{2}

and

N i C l_{4}^{2 -}

the colourless species are:

Complete the following reaction: $N a_{2} C O_{3} + H_{2} S O_{4} \to$ ___?

Complete the following reaction:

${Na}_{2} {CO}_{3} (s) + H_{2} {SO}_{4} (aq) \to ?$

Q. Complete the following reaction:

N a_{2} C O_{3} + H_{2} S O_{4} \to

____?

Two half reactions for the following equation are:
$4 H_{2} S O_{4} + K_{2} C r_{2} O_{7} + 3 N a_{2} S O_{3} ⟶ C r_{2} (S O_{4})_{3} + K_{2} S O_{4} + 3 N a_{2} S O_{4} + 4 H_{2} O$

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The colourless species is (are) :

The correct option is B Na3VO4Compound with zero unpair electron will be colourless.VCl3;23V3+;[Ar]183d2=2 unpaired electronsVO+2;V4+;[Ar]183d2=1 unpaired electron.[VO4]3−;V5+;[Ar]183d0= no unpaired electron so colourless.[V(H2O)6]2+;V2+:[Ar]183d3=3 unpaired electrons.