The colourless species is

V C l_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

V O S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{3} V O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[V (H_{2} O)_{6}] S O_{4} \cdot H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $N a_{3} V O_{4}$
$V O S O_{4}$ +4 have one d-orbital unpair electron
$V C l_{3}$ +3 have two d-orbital unpair electron
$N a_{3} V O_{4}$ +5 have no unpaired electron so no d-d transition and compound is colourless.
$[V (H_{2} O)_{6}] S O_{4} \cdot H_{2} O$ +2 have 3 unpaired electron.

Suggest Corrections

Similar questions

V C l_{3}

V O S O_{4}

N a_{3} V O_{4}

$[V {(H_{2} O)}_{6}] S O_{4} . H_{2} O$

(I) V C l_{3} (I I) V O S O_{4} (I I I) N a_{3} V O_{4} (I V) [V (H_{2} O)_{6}] S O_{4} . H_{2} O

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

Join BYJU'S Learning Program