The colourless species is:

V C l_{3}

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V O S O_{4}

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N a_{3} V O_{4}

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[V (H_{2} O)_{6}] S O_{4} . H_{2} O

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Solution

The correct option is C $N a_{3} V O_{4}$
In ${N a_{3} V O}_{4}$ , the oxidation state of vanadium is:
$3 + x - 8 = 0$
$x = 5$

Vanadium is in +5 oxidation state.

Electronic configuration of $V = [A r] 3 d^{3} 4 s^{2}$
Electronic configuration of $V^{5 +} = [A g] 3 d^{0} 4 s^{0}$

It does not have unpaired electron.

Hence, $N a_{3} V O_{4}$ is a colourless species.

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Similar questions

V C l_{3}

V O S O_{4}

N a_{3} V O_{4}

$[V {(H_{2} O)}_{6}] S O_{4} . H_{2} O$

(I) V C l_{3} (I I) V O S O_{4} (I I I) N a_{3} V O_{4} (I V) [V (H_{2} O)_{6}] S O_{4} . H_{2} O

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

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