Question

The combination of gates shown in the figure below produces.

• A. NOR gate
• B. OR gate
• C. AND gate
• D. XOR gate

Answer 1

Answer: (B)

OR gate

Here, the output of these gate
$Y=\overline{\overline{A}-\overline{B}}$
But according to Boolean algebra,
$\overline{A}\cdot \overline{B}=\overline{A+B}$
$\therefore Y=\overline{\overline{A+B}}=A+B$
or $Y=A+B$
It meas the whole circuit of gates behaves as OR gate.