The combination of ‘NAND’ gates shown here under (figure) are equivalent to –
A
An OR gate and an AND gate respectively
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B
An AND gate and a NOT gate respectively
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C
An AND gate and an OR gate respectively
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D
An OR gate and a NOT gate respectively
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Solution
The correct option is A An OR gate and an AND gate respectively For 1st combination C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A.A¯¯¯¯¯¯¯¯¯¯¯B.B
A.A. = A & B.B. = B C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯A.¯¯¯¯B C=¯¯¯¯¯¯¯¯A¯¯¯¯¯¯¯¯B
C = A + B
It is an OR gate
For 2nd combination C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A.B.¯¯¯¯¯¯¯¯¯¯¯A.B C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A.B.¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A.B
C = AB + AB
C = AB
Its an AND gate