Question

The combination of NAND gates shown in figure are equivalent to

• A. an OR gate and an AND gate respectively
• B. an AND gate and a NOT gate respectively
• C. an AND gate and an OR gate respectively
• D. an OR gate and a NOT gate respectively

Answer 1

The correct option is A an OR gate and an AND gate respectively


Case-1
$C=\overline{\overline{A}.\overline{B}}=A+B$ (De Morgan's Theorem)
So, the circuit is equivalent to OR gate .
Case-2


$C=\overline{\overline{AB}.\overline{AB}}=AB+AB=AB$
Hence the circuit is equivalent to AND gate.