The combination of NAND gates shown in figure are equivalent to
A
an OR gate and an AND gate respectively
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B
an AND gate and a NOT gate respectively
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C
an AND gate and an OR gate respectively
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D
an OR gate and a NOT gate respectively
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Solution
The correct option is A an OR gate and an AND gate respectively Case-1 C=¯¯¯¯¯¯¯¯¯¯¯A.¯¯¯B=A+B (De Morgan's Theorem) So, the circuit is equivalent to OR gate . Case-2
C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯AB.¯¯¯¯¯¯AB=AB+AB=AB Hence the circuit is equivalent to AND gate.