The combined resistance of two conductors in series is 1 - If the conductance of one conductor is 1-1 siemen- the conductance of the other conductor in siemen is

The correct option is B 11 R_1 + R_2 = 1 ⇒ #160; 1G_1 + 1G_2 = 1 11.1 = 1G_2 = 1 1G_2 = 0.11.1 G_2 = 11 ...

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Standard X

Physics

Resistivity

The combined ...

Question

The combined resistance of two conductors in series is 1 $Ω$ . If the conductance of one conductor is 1.1 siemen, the conductance of the other conductor in siemen is

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Solution

The correct option is B 11
$R_{1} + R_{2} = 1$
$\Rightarrow \frac{1}{G_{1}} + \frac{1}{G_{2}} = 1$
$\frac{1}{1.1} = \frac{1}{G_{2}} = 1$
$\frac{1}{G_{2}} = \frac{0.1}{1.1}$
$G_{2} = 11$

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The combined resistance of two conductors in series is 1Ω. If the conductance of one conductor is 1.1 siemen, the conductance of the other conductor in siemen is

The correct option is B 11R1+R2=1⇒1G1+1G2=111.1=1G2=11G2=0.11.1G2=11

The combined resistance of two conductors in series is 1 $Ω$ . If the conductance of one conductor is 1.1 siemen, the conductance of the other conductor in siemen is

The correct option is B 11
$R_{1} + R_{2} = 1$
$\Rightarrow \frac{1}{G_{1}} + \frac{1}{G_{2}} = 1$
$\frac{1}{1.1} = \frac{1}{G_{2}} = 1$
$\frac{1}{G_{2}} = \frac{0.1}{1.1}$
$G_{2} = 11$