Question

The combustion chamber of a bike has an area of cross-section $16{\text{cm}}^2$. A pressure of $400\text{Pa}$ acts on it. Find the force exerted on the bike.

Answer 1

Step 1: Given that

The combustion chamber cross-section area of the bike $\left(\text{A}\right)=16{\text{cm}}^2{\text{⇒16×10}}^{-4}\text{m}$

Pressure applied on bike $\left(P\right)=400\text{Pa}$

Step 2: The relation between pressure, normal force, and area are:

$\text{Pressure}=\frac{\text{normal force(thrust)}}{\text{area}}$

Step 3: We have to calculate normal force (thrust) by applying the formula from step 2

Now, the normal force (thrust) applied by man will be:

$\text{normal force(thrust)=Pressure×Area}$

${\text{normal force(thrust)=400 Pa×16×10}}^{-4}\text{m}$

By solving it we get

$\text{normal force(thrust)}\Rightarrow 0.64N$

Hence, the force exerted on the bike will be: $\Rightarrow 0.64N$