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Standard X

Chemistry

Classification of Hydrocarbons

The combustio...

Question

The combustion of benzene at constant volume is -3263.9 kJ $m o l^{- 1}$ at $25^{0} C$ heat of combustion ( in kJ $m o l^{- 1}$ ) of benzene at constant pressure will be:
(R=8.314 $J K^{- 1} m o l^{- 1}$ )

4152.6

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-452.46

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3260

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-3267.6

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Solution

The correct option is D -3267.6
Option D is correct.

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Similar questions

Q. The combustion of benzene

(l)

gives

C O_{2} (g)

and

H_{2} O (l)

. Given that the heat of combustion of benzene at constant volume is —3263.9

k J m o l^{- 1}

25^{\circ} C

. The heat of combustion

(i n k J m o l^{- 1})

of benzene at constant pressure will be:

(R = 8.314 J K^{- 1} m o l^{- 1})

Q. The combustion of benzene

(l)

gives

C O_{2} (g)

and

H_{2} O (l)

. Given that the heat of combustion of benzene at constant volume is —3263.9

k J m o l^{- 1}

25^{\circ} C

. The heat of combustion

(i n k J m o l^{- 1})

of benzene at constant pressure will be:

(R = 8.314 J K^{- 1} m o l^{- 1})

Q. The combustions of benzene (l) gives

C O_{2} (g)

and

H_{2} O (l)

. Given that heat of combustion of benzene at constant volume is

- 3263.9 k J m o l^{- 1}

25^{o} C

, heat of combustion (in

k J m o l^{- 1}

) of benzene at constant pressure will be:

(R = 8.314 J K^{- 1} m o l^{- 1})

Q. The heat of combustion of benzene in a bomb calorimeter (i.e., constant volume) was found to be

3263.9 k J m o l^{- 1}

25^{o} C

. Calculate the heat of combustion of benzene at constant pressure.

The heat liberated on complete combustion of $7.8 g$ benzene is $327 K J$ . This heat has been measured at constant volume and at $27^{0} C$ . What is the heat of combustion of benzene at constant pressure at $27^{0} C (R = 8.3 J m o l^{- 1} K^{- 1})$

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The combustion of benzene at constant volume is -3263.9 kJ mol−1 at 250C heat of combustion ( in kJ mol−1) of benzene at constant pressure will be: (R=8.314 JK−1mol−1)

The correct option is D -3267.6Option D is correct.

The combustion of benzene at constant volume is -3263.9 kJ $m o l^{- 1}$ at $25^{0} C$ heat of combustion ( in kJ $m o l^{- 1}$ ) of benzene at constant pressure will be:
(R=8.314 $J K^{- 1} m o l^{- 1}$ )

The correct option is D -3267.6
Option D is correct.