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Byju's Answer
Standard XII
Chemistry
Lattice Energy
The combustio...
Question
The combustion of benzene
(
I
)
gives
C
O
2
(
g
)
and
H
2
O
(
I
)
.Given that heat of combustion of benzene at,constant volume is
−
3263.9
k
J
m
o
l
−
1
at
25
o
C
; heat of combustion (in
k
J
m
o
l
−
1
)
of benzene at constant pressure will be:
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Solution
Formula,
Δ
H
=
Δ
U
+
Δ
n
g
R
T
=
−
3263.8
+
(
6
−
7.5
)
×
8.314
×
10
−
3
×
298
=
−
3267.6
k
J
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1
Similar questions
Q.
The combustion of benzene
(
l
)
gives
C
O
2
(
g
)
and
H
2
O
(
l
)
. Given that the heat of combustion of benzene at constant volume is —3263.9
k
J
m
o
l
−
1
at
25
∘
C
. The heat of combustion
(
i
n
k
J
m
o
l
−
1
)
of benzene at constant pressure will be:
(
R
=
8.314
J
K
−
1
m
o
l
−
1
)
Q.
The combustion of benzene
(
l
)
gives
C
O
2
(
g
)
and
H
2
O
(
l
)
. Given that the heat of combustion of benzene at constant volume is —3263.9
k
J
m
o
l
−
1
at
25
∘
C
. The heat of combustion
(
i
n
k
J
m
o
l
−
1
)
of benzene at constant pressure will be:
(
R
=
8.314
J
K
−
1
m
o
l
−
1
)
Q.
The heat of combustion of benzene in a bomb calorimeter (i.e., constant volume) was found to be
3263.9
k
J
m
o
l
−
1
at
25
o
C
. Calculate the heat of combustion of benzene at constant pressure.
Q.
The combustion of benzene at constant volume is -3263.9 kJ
m
o
l
−
1
at
25
0
C
heat of combustion ( in kJ
m
o
l
−
1
) of benzene at constant pressure will be:
(R=8.314
J
K
−
1
m
o
l
−
1
)
Q.
The heat of combustion of benzene in a bomb calorimeter (i.e., constant volume) was found to be
3263.9
k
J
m
o
l
−
1
at
25
o
C
. Calculate the heat of combustion of benzene at constant pressure.
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