The combustion of methane is written asCH4(g)+2O2(g)→CO2(g)+2H2O(l)The difference between enthalpy change and energy change is equal to:
What change is represented by the following equation?
CH4(g) + 202(g) →CO2(g) + 2H2O(l)
Standard enthalpy of combustion of CH4 is −890 kJ mol−1 and standard enthalpy of vaporisation of water is 40.5 kJ mol−1. Calculate the enthalpy change for the reaction : CH4(g)+2O2(g)→CO2(g)+2H2O(g)