The combustion of methane is written as CH4g-2O2g-CO2g-2H2OlThe difference between enthalpy change and energy change is equal to-

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Standard XII

Chemistry

Lattice Energy

The combustio...

Question

The combustion of methane is written as
${C H}_{4} (g) + 2 O_{2} (g) \to {C O}_{2} (g) + 2 H_{2} O (l)$
The difference between enthalpy change and energy change is equal to:

- 2 R T

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R T

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\frac{R T}{2}

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Solution

The correct option is A $- 2 R T$
$Δ H = Δ U + Δ n_{g} R T$
$Δ H - Δ U = (1 - 3) R T$
$= - 2 R T$

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Similar questions

Q. Calculate the enthalpy of formation of methane from the following data:

C (s) + O_{2} (g) \to C O_{2} (g)

;

Δ_{r} H^{\circ} = - 393.5 k J

2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O (l)

;

Δ_{r} H^{\circ} = - 571.8 k J

C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)

;

Δ_{r} H^{\circ} = - 890.3 k J

What change is represented by the following equation?

CH₄(g) + 20₂(g) →CO₂(g) + 2H₂O(l)

Q. What is the relation between

Δ H

and

Δ E

in this reaction?

C H_{4 (g)} + 2 O_{2 (g)} ⇌ C O_{2 (g)} + 2 H_{2} O_{(l)}

Q. Calculate the enthalpy change for the following reaction:

{C H}_{4} (g) + 2 O_{2} (g) ⟶ {C O}_{2} (g) + 2 H_{2} O (l)

Given, enthalpies of formation of

{C H}_{4}, {C O}_{2}

and

H_{2} O

are

74.8 k J {m o l}^{- 1}, - 393.5 k J {m o l}^{- 1}, - 286 k J {m o l}^{- 1}

respectively.

Standard enthalpy of combustion of $C H_{4}$ is $- 890 k J m o l^{- 1}$ and standard enthalpy of vaporisation of water is 40.5 kJ $m o l^{- 1}$ . Calculate the enthalpy change for the reaction :
$C H_{4 (g)} + 2 O_{2 (g)} \to C O_{2 (g)} + 2 H_{2} O_{(g)}$

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The combustion of methane is written asCH4(g)+2O2(g)→CO2(g)+2H2O(l)The difference between enthalpy change and energy change is equal to:

The correct option is A −2RTΔH=ΔU+ΔngRTΔH−ΔU=(1−3)RT=−2RT

The combustion of methane is written as
${C H}_{4} (g) + 2 O_{2} (g) \to {C O}_{2} (g) + 2 H_{2} O (l)$
The difference between enthalpy change and energy change is equal to:

The correct option is A $- 2 R T$
$Δ H = Δ U + Δ n_{g} R T$
$Δ H - Δ U = (1 - 3) R T$
$= - 2 R T$