The common chord of the circle x2+y2+4x+1=0 and x2+y2+6x+2y+3=0 is
S1=x2+y2+4x+1=0
S2=x2+y2+6x+2y+3=0
Common chord ≡S1−S2=0⇒2x+2y+2=0
⇒x+y+1=0