The common chord of $x^{2} + y^{2} - 4 x - 4 y = 0$ and $x^{2} + y^{2} = 16$ subtends at the origin an angle to

π / 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π / 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

π / 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π / 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $π / 4$
$x^{2} + y^{2} - 4 x - 4 y = 0 x^{2} + y^{2} = 16$
$x^{2} + y^{2} - 4 x - 4 y - x^{2} - y^{2} + 16 = 0$
$x + y = 4$
$\Rightarrow π / 4 =$ angle subtend

Suggest Corrections

Similar questions

x^{2} + y^{2} - 4 x - 4 y = 0

x^{2} + y^{2} = 16

x^{2} + y^{2} = 4

\frac{π}{2}

x^{2} + y^{2} = 1.

x^{2} + y^{2} = r^{2}

^{'} θ^{'}

x^{2} + y^{2} = r^{2} {cos}^{2} (\frac{θ}{2})

x^{2} + y^{2} - 4 x - 4 y = 0

2 x^{2} + 2 y^{2} = 32

y^{2} = 4 x

x^{2} + y^{2} = 5

Join BYJU'S Learning Program