The common difference of an A.P. is 10, then what is $a_{2} - a_{5}$ ?

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-30

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-25

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Solution

The correct option is C -30
Given, $d = 10$
we know that $a_{n} = a + (n - 1) d$
$a_{2} = a + (2 - 1) 10$
$a_{2} = a + 10$ ...... (1)
$a_{5} = a + (5 - 1) 10$
$a_{5} = a + 40$ ...... (2)
on subtracting equation (1) & (2) we get
$a_{2} - a_{5} = - 30$

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