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Question

The common difference of an arithmetic sequence is 1 and the product of the first and the third terms is 143. What are the first three terms?


Solution

Common difference of an arithmetic sequence = 1

Let the second term be x.

First term = x 1

Third term = x + 1 

Product of the first term and the third term = 143

(x 1)(x + 1) = 143

If x = 12, then the second term = 12

First term = x 1 = 12 1 = 11

Third term = x + 1 = 12 + 1 = 13

If x = 12, then the second term = 12

First term = x 1 = 12 1 = 13

Third term = x + 1 = 12 + 1 = 11

Therefore, the first three terms of the sequence are 11, 12, and 13 or 13, 12, and 11.


Mathematics
Mathematics Part I
Standard X

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