The common factor of 10a2 + 5b2 + 15c2 is
3
a
5
5b
10a2= 2 × 5 × a × a
5b2= 5 × b × b
15c2= 3 × 5 × c × c
The common factor is 5.
Factorize:
25(a−5b)2−4(a−3b)2
Show that: (9a−5b)2+180ab=(9a+5b)2.
Find the value of 15C2+ 2 15C3 + 3 15C4 . . . . . 14 15C15