The common oxidation state of oxygen is −2. This can be explained as:
A
2 electrons are in the first shell
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B
4 electrons are in the outermost shell
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C
6 electrons are in the outermost shell
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D
8 electrons are present in the atom
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Solution
The correct option is C6 electrons are in the outermost shell Electronic configuration of O is 2,6. It requires 2 electrons to gain inert gas configuration, so its common oxidation state of is −2